Armstrong numbers with in range using java

CODE:

import java.util.*;
class amstrong
{
public static void main(String arg[])
{
Scanner in = new Scanner(System.in);
System.out.println("enter th range");
//year=in.nextInt();
int range=in.nextInt();
int a,b,c,sum,count=0;
b=1;
while(b<=range)
{
sum= 0;
c=b;
while(c>0)
{
a = c%10;
sum =sum+(a*a*a);
c = c/10;
}
if(sum==b)
{
System.out.println(b+"is a amstrong number");
count = count+1;
}
b++;
}
System.out.println("total amstrong number present with in the range is"+count);
}

}